When \(a \ne 0\), there are two solutions to \((ax^2 + bx + c = 0)\) and they are \[x = {-b \pm \sqrt{b^2-4ac} \over 2a}.\]
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When \(a \ne 0\), there are two solutions to \((ax^2 + bx + c = 0)\) and they are \[x = {-b \pm \sqrt{b^2-4ac} \over 2a}.\]